Determine the value of k so that the equations (3k+1)x+3y=2, (k^2+1)x+(k-2)y=5 have no solution

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Determine value of k for which following equations have no solution(3k+1)x+3y-2=0,(k²+1)x+(k-2)y-5=0

| (3k+1)x+3y-2=0 (k²+1)x+(k-2)y-5 =0 | determine the value of k so that following linear equation |

Find the value of k so that the linear eq's have no solution- (3k+1)x+3y-2=0 & (k²+1)x+(k-2)y-5=0

k का मान ज्ञात कीजिए ताकि निम्न समीकरण युग्म का कोई हल नहीं हो।(3k+1)x+3y-2=0(k^(2)+1)x+(k-2)y-5...

Determine the value of k, the linear equations have no solution. (3k+1)x+3y-2=0 (k^2+1)x+(k-2)y-5=0

For what values of k will the following equations have no solution: x + 2y = 3; (k-1)x+(k+1)y=(k+2).

Find the value of k for equation 2x + 3y = 7 , (k - 1)x + (k + 2)y = 3k

How to Find Value of k when Two Linear Equations have Infinitely Many Solutions - Simple Tutorial