Determine the value of k, the linear equations have no solution. (3k+1)x+3y-2=0 (k^2+1)x+(k-2)y-5=0

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k рдХрд╛ рдорд╛рди рдЬреНрдЮрд╛рдд рдХреАрдЬрд┐рдП рддрд╛рдХрд┐ рдирд┐рдореНрди рд╕рдореАрдХрд░рдг рдпреБрдЧреНрдо рдХрд╛ рдХреЛрдИ рд╣рд▓ рдирд╣реАрдВ рд╣реЛред(3k+1)x+3y-2=0(k^(2)+1)x+(k-2)y-5... k рдХрд╛ рдорд╛рди рдЬреНрдЮрд╛рдд рдХреАрдЬрд┐рдП рддрд╛рдХрд┐ рдирд┐рдореНрди рд╕рдореАрдХрд░рдг рдпреБрдЧреНрдо рдХрд╛ рдХреЛрдИ рд╣рд▓ рдирд╣реАрдВ рд╣реЛред(3k+1)x+3y-2=0(k^(2)+1)x+(k-2)y-5...
Determine the value of k so that the equations (3k+1)x+3y=2, (k^2+1)x+(k-2)y=5 have no solution Determine the value of k so that the equations (3k+1)x+3y=2, (k^2+1)x+(k-2)y=5 have no solution
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