Let X = R×R. Define a relation R on X as : (a_1,b_1 ) R (a_2,b_2 ) ↔ b_1=b_2.Statement – I : R is

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Let X = R×R. Define a relation R on X as : (a_1,b_1 ) R (a_2,b_2 ) ↔ b_1=b_2.Statement – I : R is Let X = R×R. Define a relation R on X as : (a_1,b_1 ) R (a_2,b_2 ) ↔ b_1=b_2.Statement – I : R is
Let X=R×R. Define a relation R on X as:a1,b1Ra2,b2b1=b2Statement-I: R is an equivalence relation.Sta Let X=R×R. Define a relation R on X as:a1,b1Ra2,b2b1=b2Statement-I: R is an equivalence relation.Sta
If R be a relation for A = {1,2,3,4} to B = {1,3,5} such that (a,b) R iff a less than b then RoR-1 If R be a relation for A = {1,2,3,4} to B = {1,3,5} such that (a,b) R iff a less than b then RoR-1
Let R1 and R2 be two relation defined on R by aR1b as ab \ge 0 and aR2b as a \ge b then Let R1 and R2 be two relation defined on R by aR1b as ab \ge 0 and aR2b as a \ge b then
#136 ll Verify that R is Compatibility Relations, S={1,2,3},R={(1,1),(2,2),(3,3),(1,2),(3,1),(3,2)} #136 ll Verify that R is Compatibility Relations, S={1,2,3},R={(1,1),(2,2),(3,3),(1,2),(3,1),(3,2)}
Prove that -(a - b) = b - a (First Proof) (ILIEKMATHPHYSICS) Prove that -(a - b) = b - a (First Proof) (ILIEKMATHPHYSICS)
|a1 + a2 + ... + an| ≤ |a1| + |a2| + ... + |an| (Proof) [ILIEKMATHPHYSICS] |a1 + a2 + ... + an| ≤ |a1| + |a2| + ... + |an| (Proof) [ILIEKMATHPHYSICS]
Asertion (A): A relation R={(a,b); |a-b| is less then 2 } defined on the set A={1,2,3,4,5} is reflex Asertion (A): A relation R={(a,b); |a-b| is less then 2 } defined on the set A={1,2,3,4,5} is reflex