In the given figure, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to :(a) 30°

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If AOB is a diameter of the circle andAC=BC, then angle CAB is equal to | 9 | CIRCLES | MATHS ... If AOB is a diameter of the circle andAC=BC, then angle CAB is equal to | 9 | CIRCLES | MATHS ...
In figure, if AOB is a diameter of the circle and AC=BC, then `angle CAB` is equal to In figure, if AOB is a diameter of the circle and AC=BC, then `angle CAB` is equal to
In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to:(A) 30º (B) 60º In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to:(A) 30º (B) 60º
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In the given figure, if AOB is a diameter of the circle and AC=BC, the ∠CAB is equal .... In the given figure, if AOB is a diameter of the circle and AC=BC, the ∠CAB is equal ....
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In the given figure, BC is a diameter of the circle and ∠BAO = 60°. Then ∠ADC is equal to :(a) 30° In the given figure, BC is a diameter of the circle and ∠BAO = 60°. Then ∠ADC is equal to :(a) 30°