In the adjoining figure, DEFG is a square & BAC = 90. Prove that DE^2 = BD x EC | Class 10 Triangles

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In the given figure, DEFG is a square and ∠BAC=90°.Show that FG^2=BG×FC. SIMILAR TRIANGLES CLASS-X In the given figure, DEFG is a square and ∠BAC=90°.Show that FG^2=BG×FC. SIMILAR TRIANGLES CLASS-X
In the given figure, DEFG is a square and +BAC = 90°. Show that FG²= BG x FC In the given figure, DEFG is a square and +BAC = 90°. Show that FG²= BG x FC
In figure DEFG is a square and angle BAC is 90° Show that DE^2= BD xEC. #trianglesclass10 In figure DEFG is a square and angle BAC is 90° Show that DE^2= BD xEC. #trianglesclass10
In the given figure, DEFG is a square and angle BAC= 90^(@), Prove that (i) Delta AGF~ Delta DBG... In the given figure, DEFG is a square and angle BAC= 90^(@), Prove that (i) Delta AGF~ Delta DBG...
In the given Fig., DEFG is a square and ∠BAC=90°. Prove that (i) ΔAGF~ΔDBG (ii) ΔAGF~ΔEFG (iii) ΔDBG In the given Fig., DEFG is a square and ∠BAC=90°. Prove that (i) ΔAGF~ΔDBG (ii) ΔAGF~ΔEFG (iii) ΔDBG
DEFG is a square and angleBAC=90°. prove that (i)📐AGF~📐DBG (ii)📐AGF~📐EFC (iii)📐DBG~📐EFC (iv)DE^2=BD× DEFG is a square and angleBAC=90°. prove that (i)📐AGF~📐DBG (ii)📐AGF~📐EFC (iii)📐DBG~📐EFC (iv)DE^2=BD×
[Class 10] In figure, DEFG is a square and ∠BAC = 90°. Show that FG^2 = BG x FC - Teachoo [Class 10] In figure, DEFG is a square and ∠BAC = 90°. Show that FG^2 = BG x FC - Teachoo
In the given figure , DEFG is a square and angleBAC= 90^(@) prove that(i) triangleAGF~ triangleD... In the given figure , DEFG is a square and angleBAC= 90^(@) prove that(i) triangleAGF~ triangleD...