If A+B+C=180° then prove that: sin(B+2C)+sin(C+2A)+sin(A+2B) = 4sin(B-C)/2.sin(C-A)/2.sin(A-B)/2.

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12b) If A+B+C=πᶜ, prove that sin(B+ 2C)+sin(C+2A)+sin(A+2B) = 4sin(A-B)/2. sin(B-C)/2.sin(C-A)/2 12b) If A+B+C=πᶜ, prove that sin(B+ 2C)+sin(C+2A)+sin(A+2B) = 4sin(A-B)/2. sin(B-C)/2.sin(C-A)/2
`sin(B+2C)+sin(C+2A)+sin(A+2B)=4sin((B-C)/2)sin((C-A)/2)sin((A-B)/2` `sin(B+2C)+sin(C+2A)+sin(A+2B)=4sin((B-C)/2)sin((C-A)/2)sin((A-B)/2`
यदि A+B+C=pi हो तो सिद्ध कीजिए कि - sin(B+2C)+sin(C+2A)+sin(A+2B)=4sin(B-C)/(2)*sin(C-A)/(2)*sin... यदि A+B+C=pi हो तो सिद्ध कीजिए कि - sin(B+2C)+sin(C+2A)+sin(A+2B)=4sin(B-C)/(2)*sin(C-A)/(2)*sin...
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