CBSE 10th- If tanθ + secθ = l, then prove that secθ = (l2 + 1)/2l.

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If tanθ + secθ = l, then prove that secθ = l^2 + 1/2l . If tanθ + secθ = l, then prove that secθ = l^2 + 1/2l .
If tan theta+sec theta=l, then prove that sec theta=(l^2)+(1/2l) | Trigonometry class 10 | If tan theta+sec theta=l, then prove that sec theta=(l^2)+(1/2l) | Trigonometry class 10 |
9 If tan θ + sec θ = l, then prove that sec θ = l^2+12l 9 If tan θ + sec θ = l, then prove that sec θ = l^2+12l
if `tantheta+sectheta=l ` then prove that `tantheta=(l^2+1)/(2l)` if `tantheta+sectheta=l ` then prove that `tantheta=(l^2+1)/(2l)`
If tanθ+θ=l, then prove that θ=l^2+1/2 l (W) If tanθ+θ=l, then prove that θ=l^2+1/2 l (W)