If a²+b²=2 and c²+d²=5 find the value of (ac+bd)²+(ad-bc)²

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if a² + b² =2 and C ²+ d² = 1 then the value of (ad - bc)² + (ac - bd)² is if a² + b² =2 and C ²+ d² = 1 then the value of (ad - bc)² + (ac - bd)² is
If a²+b² = 1 and c²+d² = 2 then find the value of (ac+bd)² +(ad-bc)² | Important Question If a²+b² = 1 and c²+d² = 2 then find the value of (ac+bd)² +(ad-bc)² | Important Question
If ad is not equal to bc, then prove that the equation (a^2 +b^2 )x^2 +2(ac+bd)x+(c^2+d^2) If ad is not equal to bc, then prove that the equation (a^2 +b^2 )x^2 +2(ac+bd)x+(c^2+d^2)
If ad ≠bc, then prove that the equation.(a² + b²)x²+2(ac+bd)x+(c²+d²)=0 has no real roots. [CBS If ad ≠bc, then prove that the equation.(a² + b²)x²+2(ac+bd)x+(c²+d²)=0 has no real roots. [CBS
If a : b : : c : d then prove that (a²-c²)/(b²-d²) = ac/bd || Boards का favourite Question || If a : b : : c : d then prove that (a²-c²)/(b²-d²) = ac/bd || Boards का favourite Question ||
If the roots of the equation (a^2+b^2)x^2-2(ac+bd)x+(c^2+d^2)=0 are equal, prove that a/b=c/d... If the roots of the equation (a^2+b^2)x^2-2(ac+bd)x+(c^2+d^2)=0 are equal, prove that a/b=c/d...
#Formula (a+b)²=a²+b²+2ab #solution #Formula (a+b)²=a²+b²+2ab #solution
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