If a²+b² = 1 and c²+d² = 2 then find the value of (ac+bd)² +(ad-bc)² | Important Question

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if a² + b² =2 and C ²+ d² = 1 then the value of (ad - bc)² + (ac - bd)² is if a² + b² =2 and C ²+ d² = 1 then the value of (ad - bc)² + (ac - bd)² is
If a²+b²=2 and c²+d²=5 find the value of (ac+bd)²+(ad-bc)² If a²+b²=2 and c²+d²=5 find the value of (ac+bd)²+(ad-bc)²
If ad ≠bc, then prove that the equation.(a² + b²)x²+2(ac+bd)x+(c²+d²)=0 has no real roots. [CBS If ad ≠bc, then prove that the equation.(a² + b²)x²+2(ac+bd)x+(c²+d²)=0 has no real roots. [CBS
If a² + b² + c² + d² = 1 then the maximum value of a.b.c.d is: #fundamental If a² + b² + c² + d² = 1 then the maximum value of a.b.c.d is: #fundamental
If (a² - bc) / (a² + bc) + (b² - ac) / (b² + ac) + (c² - ab) / (c² + ab) = 1 find a² / (a² + bc) + If (a² - bc) / (a² + bc) + (b² - ac) / (b² + ac) + (c² - ab) / (c² + ab) = 1 find a² / (a² + bc) +
a²-b²+c²-d²-2(ac-bd) a²-b²+c²-d²-2(ac-bd)
How a2 - b2= (a+b)(a-b) ? #maths #algebra #formula How a2 - b2= (a+b)(a-b) ? #maths #algebra #formula
If a+b+c=0 find the value ab/a²+ab+b² +bc/b²+bc+c² +ca/c²+ca+a² If a+b+c=0 find the value ab/a²+ab+b² +bc/b²+bc+c² +ca/c²+ca+a²