class11 maths Chapter 8, show that the middle term in the expansion of (1+x)^2n is 1.3.5,rb classes

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In expansion of (1+x)^2n middle term is ((1.3.5...(2n-1))*2^n*x^n)/n! | Binomial Theorem In expansion of (1+x)^2n middle term is ((1.3.5...(2n-1))*2^n*x^n)/n! | Binomial Theorem
Show that the middle term in the expansion of `(1+x)^(2n)` is `(1. 3. 5.dotdot(2n-1))/(n !)` `2n... Show that the middle term in the expansion of `(1+x)^(2n)` is `(1. 3. 5.dotdot(2n-1))/(n !)` `2n...
Show that the middle term in the expansion of (1+x)^2n =(1.3.5..........(2n-1)2^nX^n)/n! Show that the middle term in the expansion of (1+x)^2n =(1.3.5..........(2n-1)2^nX^n)/n!
8.a) Show that middle term of expansion of (1+x)²ⁿ is [1•3•5•...•(2n–1)]/n! 2ⁿ xⁿ Math Binomial NEB 8.a) Show that middle term of expansion of (1+x)²ⁿ is [1•3•5•...•(2n–1)]/n! 2ⁿ xⁿ Math Binomial NEB
In the expansion of (1+x)^2n middle term is ((1.3.5...(2n-1))*2^n*x^n)/n! | Binomial Theorem In the expansion of (1+x)^2n middle term is ((1.3.5...(2n-1))*2^n*x^n)/n! | Binomial Theorem
Show that the middle term in the expansion of `(1+x)^(2n)` is `(1. 3. 5.dotdot(2n-1))/(n !)` `2n... Show that the middle term in the expansion of `(1+x)^(2n)` is `(1. 3. 5.dotdot(2n-1))/(n !)` `2n...
Middle Term Of A Binomial Expansion | Prove: Middle Term Of (1+x)^2n is 1.3.5.....(2n-1).2^n.x^n/n! Middle Term Of A Binomial Expansion | Prove: Middle Term Of (1+x)^2n is 1.3.5.....(2n-1).2^n.x^n/n!
Prove that the middle term in the expansion of `(x+ 1/x)^(2n)` is (1.3.5…(2n-1)/(n! ` 2^n` Prove that the middle term in the expansion of `(x+ 1/x)^(2n)` is (1.3.5…(2n-1)/(n! ` 2^n`