\( \sum_{r=1}^{n} \tan ^{-1}\left(\frac{2^{r-1}}{1+2^{2 r-1}}\right) \) is equal to (a) \( \tan ...

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Limit where n tends to ♾️ tan {Summation of r=1 to n tan^-1 (1/1+r+r^2)} is equal to: Limit where n tends to ♾️ tan {Summation of r=1 to n tan^-1 (1/1+r+r^2)} is equal to:
Q) lim_(π‘›β†’βˆž)β€Štan{βˆ‘_(π‘Ÿ=1)^π‘›β€Štan^(βˆ’1) (1/(1+π‘Ÿ+π‘Ÿ^2 ))} is #jee #jeeproblems #jeemains #class12th Q) lim_(π‘›β†’βˆž)β€Štan{βˆ‘_(π‘Ÿ=1)^π‘›β€Štan^(βˆ’1) (1/(1+π‘Ÿ+π‘Ÿ^2 ))} is #jee #jeeproblems #jeemains #class12th
How to calculate inverse tan in scientific calculator #scintific #calculator #studenthacks How to calculate inverse tan in scientific calculator #scintific #calculator #studenthacks
Integrating using t=tan(x/2) substitution - [The Weierstrass substitution] Integrating using t=tan(x/2) substitution - [The Weierstrass substitution]
∫1/(1 + x.tan(x))Β² dx [0, Ο€/2] = ?? ∫1/(1 + x.tan(x))Β² dx [0, Ο€/2] = ??
lim n tends to infinity Sum r=1 to n tan^-1(2Γ—3^r-1/1+3^2r-1) lim n tends to infinity Sum r=1 to n tan^-1(2Γ—3^r-1/1+3^2r-1)
If summation r=1 to infinity tan^-1(1/2r^2) =t, then tan t is ? Jee test series Inverse Trigonometry If summation r=1 to infinity tan^-1(1/2r^2) =t, then tan t is ? Jee test series Inverse Trigonometry
`sum_(r=1) ^n tan^-1 (2^(r-1) / (1+ 2^(2r-1))) ` is equal to `sum_(r=1) ^n tan^-1 (2^(r-1) / (1+ 2^(2r-1))) ` is equal to