`sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2`

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Prove sin^2(pi/6) + cos^2(pi/3) - tan^2(pi /4) = -1/2 Prove sin^2(pi/6) + cos^2(pi/3) - tan^2(pi /4) = -1/2
'sin^2(pi/6)+cos^2(pi/3)- tan^2(pi/4)=-1/2'
 Prove that sin^2 π/6 + cos^2 π/3 – tan^2 π/4 = – 1/2  Prove that sin^2 π/6 + cos^2 π/3 – tan^2 π/4 = – 1/2
sin^(2). pi/6 + cos^(2). pi/3 - tan^(2). pi/4 = -1/2 | CLASS 11 | त्रिकोणमितीय फलन | MATHS |... sin^(2). pi/6 + cos^(2). pi/3 - tan^(2). pi/4 = -1/2 | CLASS 11 | त्रिकोणमितीय फलन | MATHS |...
Prove that:sin^2(π/6)+cos^2(π/3)-tan^2(π/4)=(-1/2) Prove that:sin^2(π/6)+cos^2(π/3)-tan^2(π/4)=(-1/2)
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`sin^(2)pi/6+cos^(2)pi/3-tan^(2)pi/4=-1/2` `sin^(2)pi/6+cos^(2)pi/3-tan^(2)pi/4=-1/2`
`sin^2` `pi/6` `+cos^2` `pi/3` `-tan^2` `pi/4=-1/2`... `sin^2` `pi/6` `+cos^2` `pi/3` `-tan^2` `pi/4=-1/2`...