`sin^(2)pi/6+cos^(2)pi/3-tan^(2)pi/4=-1/2`

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'sin^2(pi/6)+cos^2(pi/3)- tan^2(pi/4)=-1/2'
 Prove that sin^2 π/6 + cos^2 π/3 – tan^2 π/4 = – 1/2  Prove that sin^2 π/6 + cos^2 π/3 – tan^2 π/4 = – 1/2
Prove sin^2(pi/6) + cos^2(pi/3) - tan^2(pi /4) = -1/2 Prove sin^2(pi/6) + cos^2(pi/3) - tan^2(pi /4) = -1/2
`sin^2` `pi/6` `+cos^2` `pi/3` `-tan^2` `pi/4=-1/2`... `sin^2` `pi/6` `+cos^2` `pi/3` `-tan^2` `pi/4=-1/2`...
`sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2` `sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2`
Prove that:sin^2(π/6)+cos^2(π/3)-tan^2(π/4)=(-1/2) Prove that:sin^2(π/6)+cos^2(π/3)-tan^2(π/4)=(-1/2)
Ex 3.3, 1 - Prove sin2 pi/6 + cos2 pi/3 - tan2 pi/4 = -1/2 - Teachoo Ex 3.3, 1 - Prove sin2 pi/6 + cos2 pi/3 - tan2 pi/4 = -1/2 - Teachoo
Prove that: sin ^2π/6+cos ^2π/3-tan ^2π/4=-1/2 LHS = sin ^2π/6+cos ^2π/3-tan ^2π/4 = (1/2)^2+(1... Prove that: sin ^2π/6+cos ^2π/3-tan ^2π/4=-1/2 LHS = sin ^2π/6+cos ^2π/3-tan ^2π/4 = (1/2)^2+(1...