Prove that A Simple graph n vertices k components can have at most (n-k)(n-k+1)/2 edges|Graph theory

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A simple graph with n vertices and k components has at most (n-k)(n-k+1)/2 edges | Graph Theory|M.Sc A simple graph with n vertices and k components has at most (n-k)(n-k+1)/2 edges | Graph Theory|M.Sc
A simple graph with n vertices and k components can have atmost ( n-k)(n-k+1)/2 edges.proof. A simple graph with n vertices and k components can have atmost ( n-k)(n-k+1)/2 edges.proof.
A simple graph with n vertices and k components can have at most ((n - k) * (n - k + 1) / 2 ) edges A simple graph with n vertices and k components can have at most ((n - k) * (n - k + 1) / 2 ) edges
Video 18: A simple graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges. Video 18: A simple graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges.
#9 A Simple Graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges | TAMIL #9 A Simple Graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges | TAMIL
Theorem based on components of a simple graph Theorem based on components of a simple graph
What is a Component of a Graph? | Connected Components, Graph Theory What is a Component of a Graph? | Connected Components, Graph Theory