A simple graph with n vertices and k components can have at most ((n - k) * (n - k + 1) / 2 ) edges

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A simple graph with n vertices and k components has at most (n-k)(n-k+1)/2 edges | Graph Theory|M.Sc A simple graph with n vertices and k components has at most (n-k)(n-k+1)/2 edges | Graph Theory|M.Sc
Toon aan dat het maximale aantal randen in een eenvoudige, onverbonden grafiek G met n hoekpunten... Toon aan dat het maximale aantal randen in een eenvoudige, onverbonden grafiek G met n hoekpunten...
Graph Theory | A simple graph with n vertices and k components can have atmost (n-k)(n-k+1)/2 edges Graph Theory | A simple graph with n vertices and k components can have atmost (n-k)(n-k+1)/2 edges
Video 18: A simple graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges. Video 18: A simple graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges.
A simple graph with n vertices and k components can have atmost ( n-k)(n-k+1)/2 edges.proof. A simple graph with n vertices and k components can have atmost ( n-k)(n-k+1)/2 edges.proof.
#9 A Simple Graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges | TAMIL #9 A Simple Graph with n vertices and k components can have at most (n-k)(n-k+1)/2 edges | TAMIL
Theorem based on components of a simple graph Theorem based on components of a simple graph
P. T. a graph with P. T. a graph with 'n' vertices and 'k' components has at most (n-k)(n-k+1)/2 edges.