JEE MAINS 2018 Simplify `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)`

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Show that: `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)=cos2alpha` Show that: `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)=cos2alpha`
Show that 2 sin^2 β + 4 cos (α + β) sin α sin β + cos 2 (α + β) = cos 2α #iitjee #maths Show that 2 sin^2 β + 4 cos (α + β) sin α sin β + cos 2 (α + β) = cos 2α #iitjee #maths
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