Show that: `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)=cos2alpha`

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Show that 2 sin^2 Ī² + 4 cos (Ī± + Ī²) sin Ī± sin Ī² + cos 2 (Ī± + Ī²) = cos 2Ī± #iitjee #maths Show that 2 sin^2 Ī² + 4 cos (Ī± + Ī²) sin Ī± sin Ī² + cos 2 (Ī± + Ī²) = cos 2Ī± #iitjee #maths
`2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)=` `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)=`
JEE MAINS 2018 Simplify `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)` JEE MAINS 2018 Simplify `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)`
'Cos2(alpha)=2sin^2(beta)+4cos(alpha+beta)sin(alpha+beta)+cos2(alpha+beta)'
2怖sin怗^2 Ī²+4cosā”(Ī±+Ī²)sinĪ±sinĪ²+cos2(Ī±+Ī²)= 2怖sin怗^2 Ī²+4cosā”(Ī±+Ī²)sinĪ±sinĪ²+cos2(Ī±+Ī²)=
`2 sin^(2) beta + 4 cos ( alpha + beta) sin alpha. Sinbeta+cos2 ( alpha +beta)=` `2 sin^(2) beta + 4 cos ( alpha + beta) sin alpha. Sinbeta+cos2 ( alpha +beta)=`
(2 sin^2)-4 cos (Ī±-Ī²) sin Ī± sinĪ²-cos 2(Ī±-Ī²) =cos 2Ī± | Trigonometric identities and laws (2 sin^2)-4 cos (Ī±-Ī²) sin Ī± sinĪ²-cos 2(Ī±-Ī²) =cos 2Ī± | Trigonometric identities and laws
Prove that `2 sin^2 beta + 4 cos(alpha + beta) sin alpha sin beta + cos 2(alpha + beta) = cos Prove that `2 sin^2 beta + 4 cos(alpha + beta) sin alpha sin beta + cos 2(alpha + beta) = cos