D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD

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D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.
D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC... D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC...
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that CA2 = CB.CD || Maths D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that CA2 = CB.CD || Maths
D is a point on the side BC of a ∆ABC such that ∠ADC=∠BAC show that CA^2=CB.CD | TRIANGLE[GEOMETRY] D is a point on the side BC of a ∆ABC such that ∠ADC=∠BAC show that CA^2=CB.CD | TRIANGLE[GEOMETRY]
D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA2 = CB.CD. D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA2 = CB.CD.
D is point on the side BC of ΔABC show that CA2 = CB.CD | Sides AB , AC median AD of Δ ABC . D is point on the side BC of ΔABC show that CA2 = CB.CD | Sides AB , AC median AD of Δ ABC .
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Class - 10 Ex - 6.3, Q1 to Q16 (Triangles) Part - 4 NCERT CBSE Class - 10 Ex - 6.3, Q1 to Q16 (Triangles) Part - 4 NCERT CBSE