D is a point on the side BC of a ∆ABC such that ∠ADC=∠BAC show that CA^2=CB.CD | TRIANGLE[GEOMETRY]

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D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC... D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC...
D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD.
Ex6.3,QNo13, D is a point on side BC of ΔABC such that angle ADC= BAC, show that CA^2=CB.CD, triang Ex6.3,QNo13, D is a point on side BC of ΔABC such that angle ADC= BAC, show that CA^2=CB.CD, triang
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD
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