The sum of the coefficients of the first three terms in the expansion of `(x-3/(x^2))^m ,x!=0,` ...

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(x-(3/x^2))^m;x≠0; sum 1st 3 co-efficient=559 find term of expansion with x^3 | Binomial Expansion (x-(3/x^2))^m;x≠0; sum 1st 3 co-efficient=559 find term of expansion with x^3 | Binomial Expansion
The sum of the coefficients of first three term in the expansion of `(x-3/(x^2))^m\, x!=0.` m The sum of the coefficients of first three term in the expansion of `(x-3/(x^2))^m\, x!=0.` m
The sum of the coefficients of the first three terms in the expansion of (x-3/x^2)^m, x ≠ 0, m be... The sum of the coefficients of the first three terms in the expansion of (x-3/x^2)^m, x ≠ 0, m be...
If the sum of coefficients of first three terms of (x- 3/x^2)^n is 276 then the coefficients of x^4 If the sum of coefficients of first three terms of (x- 3/x^2)^n is 276 then the coefficients of x^4
The sum of the coefficients of the first three terms in the expansion of `(x-3/(x^2))^m ,x!=0,` ... The sum of the coefficients of the first three terms in the expansion of `(x-3/(x^2))^m ,x!=0,` ...
Let the sum of the coefficients of the first three term in the expansion of 〖(x-3/x^2 )〗^n Let the sum of the coefficients of the first three term in the expansion of 〖(x-3/x^2 )〗^n
let the sum of the coefficients of the first three terms in the expansion of (x-3/x^2)^n be 376 let the sum of the coefficients of the first three terms in the expansion of (x-3/x^2)^n be 376
Binomial Theorem Expansion, Pascal Binomial Theorem Expansion, Pascal's Triangle, Finding Terms & Coefficients, Combinations, Algebra 2