D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA2=CB.CD class 10 imp

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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13 D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13
D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.
D is a point on the side BC of triangle ABC such that angle ACD = angle BAC show that AC^2= BC.DC . D is a point on the side BC of triangle ABC such that angle ACD = angle BAC show that AC^2= BC.DC .
D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC... D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC...
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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD
D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD.
D is a point on the side B C of a triangle ABC such that ∠ADC=∠BAC. Show that CA^2=CB·CD. D is a point on the side B C of a triangle ABC such that ∠ADC=∠BAC. Show that CA^2=CB·CD.