If `bgta` then show that the equation `(x-a)(x-b)-1=0` has one root less than a and other root g...

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If `bgta`, then prove that the equation `(x-a)(x-b)-1=0` has one root in `(-infty,a)` and t If `bgta`, then prove that the equation `(x-a)(x-b)-1=0` has one root in `(-infty,a)` and t
Prove following relationship given that one root of a*square(x)+bx+c=0 is nth power of the other. Prove following relationship given that one root of a*square(x)+bx+c=0 is nth power of the other.
If b greater than a then the equation (x-a)(x-b)-1=0 has (a). both the roots in [a,b]...... If b greater than a then the equation (x-a)(x-b)-1=0 has (a). both the roots in [a,b]......
If bGreater a, then the equation, (x-a)(x-b) – 1 = 0, has a)both roots in [a,b] b)both root If bGreater a, then the equation, (x-a)(x-b) – 1 = 0, has a)both roots in [a,b] b)both root
If \( ba \), then the equation \( (x-a)(x-b)-1=0 \) has (a) both roots in \( (a, b) \) (b) both ... If \( ba \), then the equation \( (x-a)(x-b)-1=0 \) has (a) both roots in \( (a, b) \) (b) both ...
3. Let a,b,c greater than zero . Then the roots of the equation ax2 + bx + c = 0 3. Let a,b,c greater than zero . Then the roots of the equation ax2 + bx + c = 0
If ba, then the equation (x-a)(x-b)-1=0, has: (A) both roots in [a, b] (B) both roots in (-∞, a) ... If ba, then the equation (x-a)(x-b)-1=0, has: (A) both roots in [a, b] (B) both roots in (-∞, a) ...
How to solve the most hardest equation in the world || x+1=x How to solve the most hardest equation in the world || x+1=x