The number of ordered pairs (r, k) for which 6. 35Cr = (k^ – 3). 36Cr + 1, where k is an integer, is

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Number of Ordered Pairs (r, k) for which 6(35Cr) = (k² – 3).36Cr+1 where k is an integer | Binomial Number of Ordered Pairs (r, k) for which 6(35Cr) = (k² – 3).36Cr+1 where k is an integer | Binomial
The number of ordered pairs (r k) for which 6.35Cr =(k²-3).36C(r+1) where k is an integer. The number of ordered pairs (r k) for which 6.35Cr =(k²-3).36C(r+1) where k is an integer.
The number of ordered pairs (r, k) for which 6 .^35C_r= (k^2-3) ·^36C_r+1, where k is an integer,... The number of ordered pairs (r, k) for which 6 .^35C_r= (k^2-3) ·^36C_r+1, where k is an integer,...
The number of ordered pairs (r,k) for which 6.(35Cr)=(k^2 -3).(36Cr+1), where k is an integer, is... The number of ordered pairs (r,k) for which 6.(35Cr)=(k^2 -3).(36Cr+1), where k is an integer, is...
If (36Cr+1)(k^2 - 3) = 6.(35Cr), Then the Ordered Pairs (r, k) are | IIT JEE Main Advanced Solution If (36Cr+1)(k^2 - 3) = 6.(35Cr), Then the Ordered Pairs (r, k) are | IIT JEE Main Advanced Solution
A8_The number of ordered pair (r,k) for which A8_The number of ordered pair (r,k) for which
The number of ordered pairs (r, k) for which 6.35C, = (k2 – 3). 36C, 41, where k is an integer, is: The number of ordered pairs (r, k) for which 6.35C, = (k2 – 3). 36C, 41, where k is an integer, is:
Know The Trick to Find the total number of Ordered Pairs of a and b | Math Olympics Know The Trick to Find the total number of Ordered Pairs of a and b | Math Olympics