If f : A to B and g : B to C are two bijections then show that g o f : A to C is also a bijection

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gof: A TO C IS BIJECTION PROOF. COMPOSITE FUNCTION OF f and g. INTER FIRST YEAR MATHS gof: A TO C IS BIJECTION PROOF. COMPOSITE FUNCTION OF f and g. INTER FIRST YEAR MATHS
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If f and g are two bijections; then gof is a bijection and `(gof)^-1 = f^-1 o g^-1` If f and g are two bijections; then gof is a bijection and `(gof)^-1 = f^-1 o g^-1`
If f : A to B , g : B to C are two bijective functions then show that (g o f)^(–1) = f^(–1) o g^(–1) If f : A to B , g : B to C are two bijective functions then show that (g o f)^(–1) = f^(–1) o g^(–1)
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If `f:A- gtB, g:B- gtC` are bijective functions show that `gof:A- gtC` is also a bijective func... If `f:A- gtB, g:B- gtC` are bijective functions show that `gof:A- gtC` is also a bijective func...
Maths 1A Functions Theorem 5 Explanation Maths 1A Functions Theorem 5 Explanation
If f:A-B,g:B-C are two bijections then (gof)inverse=f inverse o g inverse If f:A-B,g:B-C are two bijections then (gof)inverse=f inverse o g inverse