Sum of all values of θ∈[0,2π] satisfying 2 sin^2⁡θ=cos⁡2θ, 2 cos^2⁡θ=3 sin⁡θ | TE | JEE Mains 2025

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The sum of all values of θ ∈[0,2π] satisfying 2(sin)^2 θ = cos2θ and 2(cos)^2 θ = 3sinθ is The sum of all values of θ ∈[0,2π] satisfying 2(sin)^2 θ = cos2θ and 2(cos)^2 θ = 3sinθ is
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If the sum of solutions of the system of equations 2sin^2 θ - cos 2θ =0 and 2 cos ^2 θ + 3sinθ =0 If the sum of solutions of the system of equations 2sin^2 θ - cos 2θ =0 and 2 cos ^2 θ + 3sinθ =0
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Let S={θ∈(0,2π) ∶7 cos^2⁡θ-3 sin^2⁡θ-2 cos^2⁡2θ=2}. Then, the sum of roots of all the equations Let S={θ∈(0,2π) ∶7 cos^2⁡θ-3 sin^2⁡θ-2 cos^2⁡2θ=2}. Then, the sum of roots of all the equations
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The sum of all values of θ∈(0, π/2) satisfying sin ^2 2 θ+cos ^4 2 θ=3/4 is (a) 3 π/8 (b) 5 π/4 (... The sum of all values of θ∈(0, π/2) satisfying sin ^2 2 θ+cos ^4 2 θ=3/4 is (a) 3 π/8 (b) 5 π/4 (...