Q) The sum of all values of 𝜃∈[0,2𝜋] satisfying 2sin^2 𝜃=cos2𝜃 and 2cos^2 𝜃=3sin𝜃 is JEE MAINS 2025

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The sum of all values of θ ∈[0,2π] satisfying 2(sin)^2 θ = cos2θ and 2(cos)^2 θ = 3sinθ is The sum of all values of θ ∈[0,2π] satisfying 2(sin)^2 θ = cos2θ and 2(cos)^2 θ = 3sinθ is
The sum of all values of θ ∈ [0, 2π] satisfying 2 sin^2θ = cos 2θ and 2 cos² θ = 3 sin sin θ is The sum of all values of θ ∈ [0, 2π] satisfying 2 sin^2θ = cos 2θ and 2 cos² θ = 3 sin sin θ is
Sum of all values of θ∈[0,2π] satisfying 2 sin^2⁡θ=cos⁡2θ, 2 cos^2⁡θ=3 sin⁡θ | TE | JEE Mains 2025 Sum of all values of θ∈[0,2π] satisfying 2 sin^2⁡θ=cos⁡2θ, 2 cos^2⁡θ=3 sin⁡θ | TE | JEE Mains 2025
If the sum of solutions of the system of equations 2sin^2 θ - cos 2θ =0 and 2 cos ^2 θ + 3sinθ =0 If the sum of solutions of the system of equations 2sin^2 θ - cos 2θ =0 and 2 cos ^2 θ + 3sinθ =0
Let S={θ∈(0,2π) ∶7 cos^2⁡θ-3 sin^2⁡θ-2 cos^2⁡2θ=2}. Then, the sum of roots of all the equations Let S={θ∈(0,2π) ∶7 cos^2⁡θ-3 sin^2⁡θ-2 cos^2⁡2θ=2}. Then, the sum of roots of all the equations
The sum of all values of θ∈(0, π/2) satisfying sin ^2 2 θ+ cos ^4 2 θ=3/4 is: [JEE Main - 2019 (J... The sum of all values of θ∈(0, π/2) satisfying sin ^2 2 θ+ cos ^4 2 θ=3/4 is: [JEE Main - 2019 (J...
Q) The number of solutions of the equation cos2𝜃cos 𝜃/2+cos 5𝜃/2=2cos^3 5𝜃/2 in [−𝜋/2,𝜋/2] #maths Q) The number of solutions of the equation cos2𝜃cos 𝜃/2+cos 5𝜃/2=2cos^3 5𝜃/2 in [−𝜋/2,𝜋/2] #maths
Proof of sin^2(θ) + cos^2(θ)=1 | Rehan Sir | Infinity Maths Academy Proof of sin^2(θ) + cos^2(θ)=1 | Rehan Sir | Infinity Maths Academy