Solve : (1+y²)(1+ logx) dx + x dy = 0, given that y=1​ when x = 1

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Solve the differential equation: `(1+y^2)(1+logx)dx+x dy=0` given that when `x=1,\\ y=1.` Solve the differential equation: `(1+y^2)(1+logx)dx+x dy=0` given that when `x=1,\\ y=1.`
Solve the differential equation `(1+y^(2))(1+log x) dx +x dy =0,` it being given that y=1 when x=1. Solve the differential equation `(1+y^(2))(1+log x) dx +x dy =0,` it being given that y=1 when x=1.
`(1+y^(2))(1+logx)dx+xdy=0`, given y=1, when x=1 `(1+y^(2))(1+logx)dx+xdy=0`, given y=1, when x=1
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If dy/dx=e^x+y and if it is given that for x=1, y=1. Find y when x=-1 If dy/dx=e^x+y and if it is given that for x=1, y=1. Find y when x=-1