Solve the differential equation: `(1+y^2)(1+logx)dx+x dy=0` given that when `x=1,\\ y=1.`

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Solve : (1+y²)(1+ logx) dx + x dy = 0, given that y=1​ when x = 1 Solve : (1+y²)(1+ logx) dx + x dy = 0, given that y=1​ when x = 1
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`(1+y^(2))(1+logx)dx+xdy=0`, given y=1, when x=1 `(1+y^(2))(1+logx)dx+xdy=0`, given y=1, when x=1
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