The functionf(x)=log(1+ax)-log(1-bx)x is not defined at x = 0. The value which should be assigne....

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f(x)=log(1+ax)-log(1-bx)/x is not defined at x=0, find the value of f(0) for f(x) to be continuous f(x)=log(1+ax)-log(1-bx)/x is not defined at x=0, find the value of f(0) for f(x) to be continuous
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if the function `f(x)` defined by f(x)=`(log(1+a x)-\"log\"(1-b x))/x` , if `x!=0` and k if x=0... if the function `f(x)` defined by f(x)=`(log(1+a x)-\"log\"(1-b x))/x` , if `x!=0` and k if x=0...
If f(x) =log(1+ ax) - log(1 -bx) /x, x≠0 & k,x = 0 and f (x) is continuous at x = 0, then the value If f(x) =log(1+ ax) - log(1 -bx) /x, x≠0 & k,x = 0 and f (x) is continuous at x = 0, then the value
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If the f(x)`=(log(1+ax)-log(1-bx))/x`, `xne0` is continuous at x = 0 then, f(0) = ..... If the f(x)`=(log(1+ax)-log(1-bx))/x`, `xne0` is continuous at x = 0 then, f(0) = .....
Let f (x)= log(1+x/a)-log(1-x/b)/x , x≠0. Find the value of ƒ at x = 0 so that ƒ becomes continuous Let f (x)= log(1+x/a)-log(1-x/b)/x , x≠0. Find the value of ƒ at x = 0 so that ƒ becomes continuous