33 b. In ABC, if AD perpendicular BC and AD2 = BD* DC, , then prove that BAC = 90

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In △ABC, if AD ⊥ BC and AD²=BD x DC , then prove that ∠BAC=90° #cbse #cbse10th #maths In △ABC, if AD ⊥ BC and AD²=BD x DC , then prove that ∠BAC=90° #cbse #cbse10th #maths
Q35 In ∆ ABC , if AD is perpendicular to BC and AD2=BD*DC then prove that angle BAC =90° Q35 In ∆ ABC , if AD is perpendicular to BC and AD2=BD*DC then prove that angle BAC =90°
In triangle ABC ,if AD perpendicular to BC and AD² = BD × DC then prove that angle BAC = 90⁰ #cbse In triangle ABC ,if AD perpendicular to BC and AD² = BD × DC then prove that angle BAC = 90⁰ #cbse
In ∆ ABC AD perpendicular to BC and AD2=BD×CD. Prove that AB2+AC2=(BD+CD)2​#shorts #sslcexam2023 In ∆ ABC AD perpendicular to BC and AD2=BD×CD. Prove that AB2+AC2=(BD+CD)2​#shorts #sslcexam2023
In triangle ABC, if AD is perpendicular to BC and AD² = BD × DC, then prove that angle BAC = 90° In triangle ABC, if AD is perpendicular to BC and AD² = BD × DC, then prove that angle BAC = 90°
In ∆ABC, if AD⊥BC and 〖AD〗^2=BD×DC, then prove that ∠BAC=90° | Class 10 | Ch 6 Triangles | Maths PYQ In ∆ABC, if AD⊥BC and 〖AD〗^2=BD×DC, then prove that ∠BAC=90° | Class 10 | Ch 6 Triangles | Maths PYQ
In ΔABC, D⊥BC , such that AD2 = BD×CD. Prove that ΔABC is right angled at In ΔABC, D⊥BC , such that AD2 = BD×CD. Prove that ΔABC is right angled at
𝐼𝑛 ∆𝐴𝐵𝐶 𝐵𝐴𝐶=90° 𝐴𝐷 perpendicular to 𝐵𝐶 . 𝑃𝑟𝑜𝑣𝑒 𝑡ℎ𝑎𝑡 2AD2=𝐵𝐷×𝐷𝐶 𝐼𝑛 ∆𝐴𝐵𝐶 𝐵𝐴𝐶=90° 𝐴𝐷 perpendicular to 𝐵𝐶 . 𝑃𝑟𝑜𝑣𝑒 𝑡ℎ𝑎𝑡 2AD2=𝐵𝐷×𝐷𝐶