If (𝑛−1)𝐶_𝑟 =(𝑘^2−8) 𝑛𝐶_(𝑟+1) then range of 𝑘 is

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#IITJEE-2024 PAPER SOLUTION if (n-1)Cr=(k^2-8) nCr+1, then find the range of k #IITJEE-2024 PAPER SOLUTION if (n-1)Cr=(k^2-8) nCr+1, then find the range of k
(n-1)Cr =(k^2-8).nCr+1, then set of the value of k (n-1)Cr =(k^2-8).nCr+1, then set of the value of k
n-1Cr= (k2-8)nCr+1 if and only if... n-1Cr= (k2-8)nCr+1 if and only if...
Condition involving n-1Cr = (k2-8)nCr+1 if and only if Condition involving n-1Cr = (k2-8)nCr+1 if and only if
If I did this in 1734 I If I did this in 1734 I'd be World Famous
n-1Cr=(k^2-8)nCr+1, if and only if #iitjee2024 n-1Cr=(k^2-8)nCr+1, if and only if #iitjee2024
How to calculate combination ( nCr) in scientific calculator How to calculate combination ( nCr) in scientific calculator
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