If p be the length of perpendicular from origin on x/a+y/b=1 |MCQ|CBSE|Straight Line|RD Sharma|11CET

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I. If p is the length of the perpendicular from the origin on the line `x/a+y/b=1 and a^2,p^ I. If p is the length of the perpendicular from the origin on the line `x/a+y/b=1 and a^2,p^
If p is the length of perpendicular from origin.......| NCERT Straight line If p is the length of perpendicular from origin.......| NCERT Straight line
If p is the length of perpendicular from the origin to the linewhose intercepts on the axes are ... If p is the length of perpendicular from the origin to the linewhose intercepts on the axes are ...
If p is the length of perpendicular from the origin on the line x/a + y/b = 1 and a2, p2, b2 are.. If p is the length of perpendicular from the origin on the line x/a + y/b = 1 and a2, p2, b2 are..
If p is the length of perpendicular from the origin on the line `(x)/(a)+(y)/(b)=1` and If p is the length of perpendicular from the origin on the line `(x)/(a)+(y)/(b)=1` and
reduce x/a+y/b=1 to normal form.show x/a^2+y/b^2=1/p^2 here p is perpendicular distance from origin reduce x/a+y/b=1 to normal form.show x/a^2+y/b^2=1/p^2 here p is perpendicular distance from origin
Ifis the length of perpendicular from the origin to the line whose intercepts on the axes are a a... Ifis the length of perpendicular from the origin to the line whose intercepts on the axes are a a...
if p is the perpendicular distance from origin to line x/a+y/b=1 then show that (1/p^2)=1/a^2+1/b^2. if p is the perpendicular distance from origin to line x/a+y/b=1 then show that (1/p^2)=1/a^2+1/b^2.