In ∆PQR, N is point on PR, such that QN perpendicular PR. If PN×NR=QN^2, Prove that angle PQR=90° |

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In a triangle PQR, N is a point on PR such that QN⊥PR. If PN . NR=QN^2, prove that ∠PQR=90^∘. (W) In a triangle PQR, N is a point on PR such that QN⊥PR. If PN . NR=QN^2, prove that ∠PQR=90^∘. (W)
In a triangle ∆PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove that ∠PQR = 90° In a triangle ∆PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove that ∠PQR = 90°
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In a ∆PQR, N is a point on PR, such that QN perpendicular to PR. If PNxNR=QN^2, Prove angle PQR=90° In a ∆PQR, N is a point on PR, such that QN perpendicular to PR. If PNxNR=QN^2, Prove angle PQR=90°
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