In a ∆PQR, N is a point on PR, such that QN perpendicular to PR. If PNxNR=QN^2, Prove angle PQR=90°

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In a triangle ∆PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove that ∠PQR = 90° In a triangle ∆PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove that ∠PQR = 90°
In a triangle PQR, N is a point on PR such that QN is perpendicular to PR. If PN.NR = QN^2, then In a triangle PQR, N is a point on PR such that QN is perpendicular to PR. If PN.NR = QN^2, then
In a triangle PQR, N is a point on PR such that QN⊥PR. If PN . NR=QN^2, prove that ∠PQR=90^∘. (W) In a triangle PQR, N is a point on PR such that QN⊥PR. If PN . NR=QN^2, prove that ∠PQR=90^∘. (W)
In ∆PQR, N is point on PR, such that QN perpendicular PR. If PN×NR=QN^2, Prove that angle PQR=90° | In ∆PQR, N is point on PR, such that QN perpendicular PR. If PN×NR=QN^2, Prove that angle PQR=90° |
In a Triangle PQR, N is a point on PR, such that QN is perpendicular PR If PN x NR = QN^2 prove that In a Triangle PQR, N is a point on PR, such that QN is perpendicular PR If PN x NR = QN^2 prove that
In triangle PQR N is a point on PR In triangle PQR N is a point on PR
how to find perpendicular in a right angle triangle|| how to find perpendicular in a right angle triangle||
In a △PQR, PR²-PQ² = QR² and M is a point on side PR such that QM⊥PR. Prove that QM² = PM×MR. In a △PQR, PR²-PQ² = QR² and M is a point on side PR such that QM⊥PR. Prove that QM² = PM×MR.