value of log(ab)- log (a/b) - logb^2

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Is not a log property log(a)-log(b)=log(a-b) Is not a log property log(a)-log(b)=log(a-b)
log(a/b)=loga-logb || ln(a/b)=lna-lnb Proof of Logarithm Rule log(a/b)=loga-logb || ln(a/b)=lna-lnb Proof of Logarithm Rule
Logarithms 2 - Part 2 Proving loga-logb=log(a/b) Logarithms 2 - Part 2 Proving loga-logb=log(a/b)
If `a^(2)+b^(2)=23ab`, then prove that `log(a+b)/5=1/2(loga+logb)` If `a^(2)+b^(2)=23ab`, then prove that `log(a+b)/5=1/2(loga+logb)`
Prove logA-logB=log(A/B) Prove logA-logB=log(A/B)
If `log((a+b)/2)=1/2(loga+logb),s h o w t h a t(a+b)/2=sqrt(a b)anda^2+b^2=2a b` If `log((a+b)/2)=1/2(loga+logb),s h o w t h a t(a+b)/2=sqrt(a b)anda^2+b^2=2a b`
Mixed: Does log(A/B)=logA-logB. If log(A+B)=logA+logB, how much is A? Mixed: Does log(A/B)=logA-logB. If log(A+B)=logA+logB, how much is A?
If `log ((a-b)/2)=1/2(loga+logb),` show that `a^2+b^2=6ab` If `log ((a-b)/2)=1/2(loga+logb),` show that `a^2+b^2=6ab`