JEE Trigonometry Sin2A+sin2B+sin2C=4sinAsinBsinC given A+B+C=180;#Jeemainstrigonometry #mathstutor

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If A + B + C = 180, Prove that sin2A + sin2B + sin2C = 4 sinA sinB sinC If A + B + C = 180, Prove that sin2A + sin2B + sin2C = 4 sinA sinB sinC
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