In the given figure, D is a point on the side BC Of ∆ABC such that ∠ADC = ∠BAC Show that CA^2=CD .CB

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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13 D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13
Ex6.3,QNo13, D is a point on side BC of ΔABC such that angle ADC= BAC, show that CA^2=CB.CD, triang Ex6.3,QNo13, D is a point on side BC of ΔABC such that angle ADC= BAC, show that CA^2=CB.CD, triang
In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB. In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB.
(a) In the given figure, D is a point on the side BC of △ABC such that ∠ADC = ∠BAC. Show that CA² (a) In the given figure, D is a point on the side BC of △ABC such that ∠ADC = ∠BAC. Show that CA²
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD
D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.
D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD.
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD