In Fig. 8.77, O is the centre of the circle and BCD is tangent to it at C. Prove that ∠BAC+∠ACD= 90°

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In given figure, O is centre of circle and ∠BCD is tangent to it at C, prove that ∠BAC + ∠ACD = 90°. In given figure, O is centre of circle and ∠BCD is tangent to it at C, prove that ∠BAC + ∠ACD = 90°.
Q26(a) In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that Q26(a) In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that
In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that ∠BAC + In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that ∠BAC +
O is the centre of the circle and BCD is tangent to it at C | Prove that opposite sides of a O is the centre of the circle and BCD is tangent to it at C | Prove that opposite sides of a
O is the center of the circle and BCD is a tangent to it at C. Prove that BAC + ACD =90° O is the center of the circle and BCD is a tangent to it at C. Prove that BAC + ACD =90°
🦕Prove 📐BAC +📐ACD=90° if BCD is Tangent to Circle at C. 🦕Prove 📐BAC +📐ACD=90° if BCD is Tangent to Circle at C.
In the given figure, O is the center of the circle and BCD is tangent to it at C. Prove that ∠BAC In the given figure, O is the center of the circle and BCD is tangent to it at C. Prove that ∠BAC
O is the centre of the circle and B C D is tangent to it at C. Prove that ∠ B A C+∠ A C D=90... O is the centre of the circle and B C D is tangent to it at C. Prove that ∠ B A C+∠ A C D=90...