If [(9^n×3^2×3^n - 27^n)÷(3^3m×2^3)]=1/27 then prove that m-n=1 #class9 #numbersystem #exponents

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If 9^n*3^2*3^n-27^n/3^3m*2^3 = 1/27, prove that m-n=1 | Easiest way to solve properties of exponents If 9^n*3^2*3^n-27^n/3^3m*2^3 = 1/27, prove that m-n=1 | Easiest way to solve properties of exponents
If 9^n × 3^2 × 3^n - 27^n / 3^3m × 2^3 = 1/27, prove that m - n = 1. If 9^n × 3^2 × 3^n - 27^n / 3^3m × 2^3 = 1/27, prove that m - n = 1.
If `(9^(n+2) xx (3^(-n/2))^(-2)-27^n)/(3^(3m)xx2^3xx10)=1/27` prove that m-n=1 If `(9^(n+2) xx (3^(-n/2))^(-2)-27^n)/(3^(3m)xx2^3xx10)=1/27` prove that m-n=1
if 9^n*3^2*3^n-27^n/3^3m*2^3=1/27 prove that m-n=1| RD Sharma class 9 maths chapter 2 Example 6 if 9^n*3^2*3^n-27^n/3^3m*2^3=1/27 prove that m-n=1| RD Sharma class 9 maths chapter 2 Example 6
If `(9^(n)xx3^(2)xx(3^(-n//2))^(-2)-(27)^(n))/(3^(3m)xx2^(3))=(1)/(27)`, prove that m-n=1. If `(9^(n)xx3^(2)xx(3^(-n//2))^(-2)-(27)^(n))/(3^(3m)xx2^(3))=(1)/(27)`, prove that m-n=1.
Q65 | If (9^n×3^2×3^n-(27)^n)/(3^3m×2^3)=3^(-3), prove that m-n=1 Q65 | If (9^n×3^2×3^n-(27)^n)/(3^3m×2^3)=3^(-3), prove that m-n=1
if `{9^n*3^2*(3^(-n/2)^(-2))-27^n}/(3^(3m)*2^3)=1/27` then prove that `m-n=1` if `{9^n*3^2*(3^(-n/2)^(-2))-27^n}/(3^(3m)*2^3)=1/27` then prove that `m-n=1`
if 9^n*3^2*3^n-27^n/3^3m*2^3=1/27 prove that m-n=1| RD Sharma class 9 maths chapter 2 Example 6 if 9^n*3^2*3^n-27^n/3^3m*2^3=1/27 prove that m-n=1| RD Sharma class 9 maths chapter 2 Example 6