If `x=1+log_abc,y=1+log_bca,z=1+log_cab`, then `(xyz)/(xy+yz+zx)` is equal to

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If `x=1+log_a bc, y=1+log_b ca, z=1+log_c ab` then prove that `xyz=xy+yz+zx` If `x=1+log_a bc, y=1+log_b ca, z=1+log_c ab` then prove that `xyz=xy+yz+zx`
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If `x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab`, then `(xyz)/(xy+yz+zx)` is equal to If `x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab`, then `(xyz)/(xy+yz+zx)` is equal to
Given x = 1+log_a⁡bc; y = 1+log_b⁡ca; z = 1+log_c⁡ab, show that xy + yz + zx = xyz. LOGARITHMS Given x = 1+log_a⁡bc; y = 1+log_b⁡ca; z = 1+log_c⁡ab, show that xy + yz + zx = xyz. LOGARITHMS
If x = 1 + loga bc, y = 1 + logb ca, z = 1 + logc ab, then xyzxy+yz+zx is equal to.... If x = 1 + loga bc, y = 1 + logb ca, z = 1 + logc ab, then xyzxy+yz+zx is equal to....
"If `x=1+(log)_a b c ,\\ y=1+(log)_b c a\\ a n d\\ z=1+(log)_c a b ,\\ `then prove tha "If `x=1+(log)_a b c ,\\ y=1+(log)_b c a\\ a n d\\ z=1+(log)_c a b ,\\ `then prove tha
If x(y+z-x)/logx=y(z+x-y)/logy=z(x+y-z)/logz then prove that x^y.y^x=z^y.y^z=x^z.z^x. If x(y+z-x)/logx=y(z+x-y)/logy=z(x+y-z)/logz then prove that x^y.y^x=z^y.y^z=x^z.z^x.