If α and β be two of x^2-64x+256=0. Then the values of (α^3/β^5 )^(1/8)+(β^3/α^5 )^(1/8) is

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If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0.the value of (𝛼^3/𝛽^5 )^(1/8)+(𝛽^3/𝛼^5 )^(1/8)

If α and β be two roots of the equation x^2-64 x+256=0. Then the value of (α^3/β^5)^1 / 8+(β^3/α^...

If α and β be two roots of the equation x2-64x+256=0. Then the (α^3/β^5)^(1/8)+(β^3/α^5 )^(1/8) is

If α and β be two roots of the equation x^2 – 64x + 256 =0. Then the value of (α^3/β^5)^(1/8) + (β^3

If α and β are two roots of the equation x²-64x+256=0,then the value of(α^3/β^5)^1/8+(β^3/α^5)^1/8

If alpha and beta be two roots of the equation x^2-64x+256=0.Then the value of [alpha^3/beta^5]^1/8+

JEE Main 2020: If α and β be two roots of the equation x²-64x+256=0. Then the value of (α³/β⁵)^1/8

If α & β be two roots of the equation x²-64x+256=0 . Then the value of (α³/β^5)^1/8 + (β³/α^5)^1/8