In triangle ACB, angle C = 90⁰ CD is perpendicular to AB, then prove that BC²/AC² = BD/AD

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In figure ∠ACB=90 & CD⊥ AB, Prove that CD²=BD×AD In figure ∠ACB=90 & CD⊥ AB, Prove that CD²=BD×AD
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In a Triangle ABC, angle ACB=90 and CD is perpendicular to AB Prove that CB2/CA2=BD/AD | Triangles In a Triangle ABC, angle ACB=90 and CD is perpendicular to AB Prove that CB2/CA2=BD/AD | Triangles
In the given figure, ∠𝑨𝑪𝑩 = 𝟗𝟎° and 𝑪𝑫 ⊥ 𝑨𝑩, Prove that 𝑪𝑫^𝟐 = 𝑩𝑫 × 𝑨𝑫. In the given figure, ∠𝑨𝑪𝑩 = 𝟗𝟎° and 𝑪𝑫 ⊥ 𝑨𝑩, Prove that 𝑪𝑫^𝟐 = 𝑩𝑫 × 𝑨𝑫.
In the given figure AD is perpendicular to BC then prove that AB²+CD²=BD²+AC² | class 10 maths In the given figure AD is perpendicular to BC then prove that AB²+CD²=BD²+AC² | class 10 maths
In the given Fig., ∠ACB=90° and CD⊥AB. Prove that CB^2/CA^2=BD/AD. In the given Fig., ∠ACB=90° and CD⊥AB. Prove that CB^2/CA^2=BD/AD.
Examples10,12-∠ACB=90° and CD⊥AB. Prove that BC2/AC2= BD/AD; if AD ⊥ BC, prove that AB2+CD2 =BD2+AC2 Examples10,12-∠ACB=90° and CD⊥AB. Prove that BC2/AC2= BD/AD; if AD ⊥ BC, prove that AB2+CD2 =BD2+AC2
In Tamil, In the figure ∠ACB = 90° and CD⊥AB, prove that CD² = BD × AD | Triangle 6| class 10 ncert In Tamil, In the figure ∠ACB = 90° and CD⊥AB, prove that CD² = BD × AD | Triangle 6| class 10 ncert