If 1/(2.3.4) + 1/(3.4.5) + 1/(4.5.6) +... = k/101, then 34k is | JEE Main Solution 2022 July #AYMQB

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If 1/(2.3.4) + 1/(3.4.5) + 1/(4.5.6) +... = k/101 | JEE Main & Advanced Solution | 2022 July #AYMQB If 1/(2.3.4) + 1/(3.4.5) + 1/(4.5.6) +... = k/101 | JEE Main & Advanced Solution | 2022 July #AYMQB
Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee
If 1/2.3.4 + 1/3.4.5 +....+ 1/100.101.102 = k/101, then 34 k is equal If 1/2.3.4 + 1/3.4.5 +....+ 1/100.101.102 = k/101, then 34 k is equal
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Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee
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Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee
Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee Q) If 1/(2Γ—3Γ—4)+1/(3Γ—4Γ—5)+1/(4Γ—5Γ—6) +…..+1/(100Γ—101Γ—102)=π‘˜/101, then 34 k #jeemains #class12 #jee