Q) If 1/(2×3×4)+1/(3×4×5)+1/(4×5×6) +…..+1/(100×101×102)=𝑘/101, then 34 k #jeemains #class12 #jee

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Q) If 1/(2×3×4)+1/(3×4×5)+1/(4×5×6) +…..+1/(100×101×102)=𝑘/101, then 34 k #jeemains #class12 #jee Q) If 1/(2×3×4)+1/(3×4×5)+1/(4×5×6) +…..+1/(100×101×102)=𝑘/101, then 34 k #jeemains #class12 #jee
If 1/2×3×4 + 1/3×4×5 +1/4×5×6+...+1/100×101×102 = k/101, then 34 k is equal to If 1/2×3×4 + 1/3×4×5 +1/4×5×6+...+1/100×101×102 = k/101, then 34 k is equal to
If 1/2.3.4 + 1/3.4.5 +....+ 1/100.101.102 = k/101, then 34 k is equal If 1/2.3.4 + 1/3.4.5 +....+ 1/100.101.102 = k/101, then 34 k is equal
If 1/(2.3.4) + 1/(3.4.5) + 1/(4.5.6) +... = k/101, then 34k is | JEE Main Solution 2022 July #AYMQB If 1/(2.3.4) + 1/(3.4.5) + 1/(4.5.6) +... = k/101, then 34k is | JEE Main Solution 2022 July #AYMQB
Q) The sum ∑_(𝑛=1)^21 3/((4𝑛−1)(4𝑛+3)) is equal to #jeemains #class12 #jee #maths #class12th Q) The sum ∑_(𝑛=1)^21 3/((4𝑛−1)(4𝑛+3)) is equal to #jeemains #class12 #jee #maths #class12th
If 1/(2.3.4) + 1/(3.4.5) + 1/(4.5.6) +... = k/101 | JEE Main & Advanced Solution | 2022 July #AYMQB If 1/(2.3.4) + 1/(3.4.5) + 1/(4.5.6) +... = k/101 | JEE Main & Advanced Solution | 2022 July #AYMQB
Q) The value of (1×2^2+2×3^2+…+100×(101)^2)/(1^2×2+2^2×3+…+100^2×101) # #jeemains #maths #class Q) The value of (1×2^2+2×3^2+…+100×(101)^2)/(1^2×2+2^2×3+…+100^2×101) # #jeemains #maths #class
Q) The sum ∑_(𝑛=1)^21 3/((4𝑛−1)(4𝑛+3)) is equal to #jeemains #class12 #jee #maths #class12th Q) The sum ∑_(𝑛=1)^21 3/((4𝑛−1)(4𝑛+3)) is equal to #jeemains #class12 #jee #maths #class12th