Arithmetic progression . problem 3.9. Ex-3 . Given a = 3, n = 8, S = 192 find d

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(ix) Given a = 3, n = 8, S = 192 , find d.#shorts #arithmeticprogression #cbseclass10 #sslc maths (ix) Given a = 3, n = 8, S = 192 , find d.#shorts #arithmeticprogression #cbseclass10 #sslc maths
Ex:5.3 Q-3. In an AP: (ix) given a = 3, n = 8, S = 192, find d Ex:5.3 Q-3. In an AP: (ix) given a = 3, n = 8, S = 192, find d
Ex 5.3, 3 (ix) - In an AP (ix) Given a = 3, n = 8, S = 192, find d - Teachoo Ex 5.3, 3 (ix) - In an AP (ix) Given a = 3, n = 8, S = 192, find d - Teachoo
In an AP a=3, n=8, S=192, find d. In an AP a=3, n=8, S=192, find d.
in an ap given a=3 n=8 s=192 find d in an ap given a=3 n=8 s=192 find d
In an AP a=3,n=8 and Sn=192 then value of d is In an AP a=3,n=8 and Sn=192 then value of d is
In AP a= 3, n= 8, sum of term is 192 find common difference d | Its Study time| cl-10 Ex-5.3-3(ix) In AP a= 3, n= 8, sum of term is 192 find common difference d | Its Study time| cl-10 Ex-5.3-3(ix)
Ques:-(ix) given a = 3 n = 8 S = 192 find d. Ques:-(ix) given a = 3 n = 8 S = 192 find d.