If in `DeltaABC,2b^(2)=a^(2)+c^(2)`, then `(sin3B)/(sinB)` is equal to

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Show that:det [[a - b - c, 2a, 2a], [2b, b - c - a, 2b], [2c, 2c, c - a - b]] = (a + b + c) ^ 3 Show that:det [[a - b - c, 2a, 2a], [2b, b - c - a, 2b], [2c, 2c, c - a - b]] = (a + b + c) ^ 3
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#Formula (a+b)²=a²+b²+2ab #solution #Formula (a+b)²=a²+b²+2ab #solution