7#DeMoivre's Theorem If Z = CiS θ then show that [Z^(2n) - 1] / [Z^(2n) + 1] = i Tan(nθ)

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Z = Cis (theta) then Z^(2n) - 1 / Z^(2n) + 1 = i tan n(theta)@EAG Z = Cis (theta) then Z^(2n) - 1 / Z^(2n) + 1 = i tan n(theta)@EAG
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