In fig PS is the bisector of angle QPR and PT is perpendicular to QR Show that angle TPS is equal

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PS is the bisector of angle QPR and PT is perpendicular to QR. Show that ∠TPS=1/2 (∠Q-∠R) PS is the bisector of angle QPR and PT is perpendicular to QR. Show that ∠TPS=1/2 (∠Q-∠R)
Class 9 –Triangles & Angles-RD Sharma-Pg 11.8 Ex13, PS is the bisector of ∠QPR, ∠TPS=1/2(∠Q - ∠R) Class 9 –Triangles & Angles-RD Sharma-Pg 11.8 Ex13, PS is the bisector of ∠QPR, ∠TPS=1/2(∠Q - ∠R)
Class 9 Maths ,In figure ,PS is the bisector of ∠QPR and PT⊥QR Show that TPS= 1/2 (∠Q-∠R). Class 9 Maths ,In figure ,PS is the bisector of ∠QPR and PT⊥QR Show that TPS= 1/2 (∠Q-∠R).
In Fig. 6.17, ∠Q ∠R, PA is the bisector of ∠QPR and PM perpendicular QR Prove that APM=1/2 (∠Q -∠R) In Fig. 6.17, ∠Q ∠R, PA is the bisector of ∠QPR and PM perpendicular QR Prove that APM=1/2 (∠Q -∠R)
In the given figure, Angle Q is greater than Angle R, M is point on QR, P is the Bisector of QPR. In the given figure, Angle Q is greater than Angle R, M is point on QR, P is the Bisector of QPR.
In Figure `P S` is the bisector of `/_Q P R` and `P T_|_Q R` . Show that `/_T P S=1/2(/_Q-/_R)do... In Figure `P S` is the bisector of `/_Q P R` and `P T_|_Q R` . Show that `/_T P S=1/2(/_Q-/_R)do...
In Fig 7.51, `` `P R\\ gt \\ P Q` and PS bisects `/_Q P R` . Prove that `/_P S R\\ gt /_P S Q` .... In Fig 7.51, `` `P R\\ gt \\ P Q` and PS bisects `/_Q P R` . Prove that `/_P S R\\ gt /_P S Q` ....
7. In Fig. 6.17, PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM =1/2( ∠Q – ∠R). 7. In Fig. 6.17, PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM =1/2( ∠Q – ∠R).