Q33(b) In ABC, if AD BC and AD2 = BD*DC, then prove that Angle BAC = 90°.

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33 b. In ABC, if AD perpendicular BC and AD2 = BD* DC, , then prove that BAC = 90 33 b. In ABC, if AD perpendicular BC and AD2 = BD* DC, , then prove that BAC = 90
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𝐼𝑛 ∆𝐴𝐵𝐶 𝐵𝐴𝐶=90° 𝐴𝐷 perpendicular to 𝐵𝐶 . 𝑃𝑟𝑜𝑣𝑒 𝑡ℎ𝑎𝑡 2AD2=𝐵𝐷×𝐷𝐶 𝐼𝑛 ∆𝐴𝐵𝐶 𝐵𝐴𝐶=90° 𝐴𝐷 perpendicular to 𝐵𝐶 . 𝑃𝑟𝑜𝑣𝑒 𝑡ℎ𝑎𝑡 2AD2=𝐵𝐷×𝐷𝐶