In given figure, ∠ACB=900 and CD⊥AB. then prove that CB2/CA2=BDAD

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In figure ∠ACB=90 & CD⊥ AB, Prove that CD²=BD×AD In figure ∠ACB=90 & CD⊥ AB, Prove that CD²=BD×AD
In the given Fig., ∠ACB=90° and CD⊥AB. Prove that CB^2/CA^2=BD/AD. In the given Fig., ∠ACB=90° and CD⊥AB. Prove that CB^2/CA^2=BD/AD.
In the given figure, ∠𝑨𝑪𝑩 = 𝟗𝟎° and 𝑪𝑫 ⊥ 𝑨𝑩, Prove that 𝑪𝑫^𝟐 = 𝑩𝑫 × 𝑨𝑫. In the given figure, ∠𝑨𝑪𝑩 = 𝟗𝟎° and 𝑪𝑫 ⊥ 𝑨𝑩, Prove that 𝑪𝑫^𝟐 = 𝑩𝑫 × 𝑨𝑫.
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In the given figure, ∠ A C B=90^∘ and C D ⊥ A B. Prove that B C^2/A C^2=B D/A D. In the given figure, ∠ A C B=90^∘ and C D ⊥ A B. Prove that B C^2/A C^2=B D/A D.
In triangle ACB, angle C = 90⁰ CD is perpendicular to AB, then prove that BC²/AC² = BD/AD In triangle ACB, angle C = 90⁰ CD is perpendicular to AB, then prove that BC²/AC² = BD/AD
In figure, angleACB=90° and CD perpendicular to AB, prove that CD^2=BD×AD. In figure, angleACB=90° and CD perpendicular to AB, prove that CD^2=BD×AD.
[Triangles] In figure, ∠ACB = 90° and CD perpendicular AB. Prove that BC^2/AC^2 = BD/AD. [Triangles] In figure, ∠ACB = 90° and CD perpendicular AB. Prove that BC^2/AC^2 = BD/AD.